Find the equation of the line between the points (8,--6)

I didn't know what form you wanted the line in.

Slope-intercept form: y=2x-20

Standard form:  2x-y=20

Point-slope form: y+4=2(x-8) or y+6=2(x-7)

You gave the points (8,-4) and (7,-6).

That last point was (7,-6) right?  I seen (7-6) and just thought you probably meant (7,-6.

Step-by-step explanation:

Equation of a line in slope-intercept form is y=mx+b where m is the slope and b is the y-intercept.

To find the slope: I'm going to line up the points vertically and subtract them vertically, then put 2nd difference over 1st difference.

I feel like some people like this more than the formula or . It is the same thing just a different way to organize things.

So let's do the finding of the slope:

( 8  ,  -4)

-( 7  ,  -6)

-------------

 1        2

So the slope is 2/1=2.

So we have m=2.

Let's input into our equation y=2x+b.

We need to find the y-intercept.  We could do that by using a point on the line. We get to choose between (8,-4) or (7,-6).  It does not matter.

y=2x+b with (8,-4)

-4=2(8)+b

-4=16+b

Subtract 16 on both sides:

-4-16=b

-20=b

So the y-intercept is -20.

The equation is y=2x+-20 or y=2x-20 (your pick-same thing).

Now let's also put it in standard form which is ax+by=c where it is preferable to have a,b, and c as integers. (Integers are {...,-3,-2,-1,0,1,2,3,...}.)

y=2x-20

Subtract 2x on both sides:

-2x+y=-20

This is in ax+by=c form.

You could multiply both sides by -1:

2x-y=20.

This is still in standard form.

Let's also go for point-slope form which is y-y1=m(x-x1) where (x1,y1) is a given point on the line and m is the slope.

We already have the slope is 2.

We have two points to choose from.  Choose one and go with it. Let's choose (x1,y1)=(8,-4).

y-(-4)=2(x-8)

or

y+4=2(x-8)

Now if you did go with the other point (x1,y1)=(7,-6) it would be:

y-(-6)=2(x-7)

y+6=2(x-7)

You are probably wondering how those are the same lines.  Let's confirm.  Solve both of them for y.

y+4=2(x-8)

Distribute 2:

y+4=2x-16

Subtract 4 on both sides:

y=2x-16-4

Simplify:

y=2x-20

Now the other line:

y+6=2(x-7)

Distribute 2:

y+6=2x-14

Subtract 6 on both sides:

y=2x-14-6

y=2x-20

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

answer: haha (: i’ll go see what it is

step-by-step explanation: