Afly undergoes a displacement of -5.80m while accelerating at -1.33m/s^2 for 4.22s. what was the initial velocity of the fly

3.94ms-¹

Step-by-step explanation:

s=-5.80, a=-1.33ms-², t=4.22s, u=?(where u is initial velocity)

v=displacement/time

v=s/t

v=-5.80/4.22

v=-1.37ms-¹

using this equation of motion

v=u+at

-1.37=u +(-1.33) x 4.22

making u the subject of the formula

u=v-at

u= -1.37 -(-1.33) x 4.22

u= -1.37 +1.33 x 4.22

u= -1.37+5.61

u= 3.94ms-¹

you have 6 equal triangles, find the area of one of them (b*h/2) and multiply by 6

(8*4: 2)*6 =

32 cm² is your answer