The time spent waiting in the line is approximately normally distributed. the mean waiting time is 6 minutes and the standard deviation of the waiting time is 2 minutes. find the probability that a person will wait for more than 4 minutes.

0.034

Step-by-step explanation:

Data:

Let the standard deviation be :

The mean be:

Therefore, P (x>4) which is  the probability that a person will wait for more than 4 minutes is given by:

 =

Therefore,

P(x > 4)  = P (z > -1)

             = P (z < -1)

From the z-tables, we find 0.034

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

answer: i feel you honey.

step-by-step explanation: