Determine whether the function in the graph is even or odd

both

Step-by-step explanation:

The correct option is:

The function is even because it is symmetric with respect to the y-axis

The function is even if its graph is symmetric with respect to the y-axis

and it is odd if its graph is symmetric with respect to the origin.

Clearly as we can see from the graph that the function is symmetric with respect to the y-axis

Hence, the given function is an even function.

So, the correct option is:

The function is even because it is symmetric with respect to the y-axis

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead