Arianna kicks a soccer ball off the ground and into the air with an initial velocity of 42 feet per second. assume the starting height of the ball is 0 feet. approximately what maximum height does the soccer ball reach? 1.3 ft 2.6 ft 26.0 ft 27.6 ft

Option D.

Step-by-step explanation:

Arianna kicks a soccer ball into the air with an initial velocity = 42 feet per second

If the starting height of the ball is 0 feet then we have to find the approximate maximum height the soccer ball attached.

Since we know vertical motion is represented by

v² = u² - 2gh

Where v = final velocity of the object

u = initial velocity of the object

g = gravitational force

h = h = maximum height achieved by the object

Here v = 0, u = 42 feet per second and g = 32 feet per second²

Now we plug in these values in the formula

0 = (42)² - 2(32)(h)

1764 = 64h

h = 27.56 feet

  ≈ 27.60 feet

Therefore, maximum height achieved by the soccer ball is 27.6 feet.

Option D is the answer.

proofs involving isosceles triangles often require special consideration because an isosceles triangle has several distinct properties that do not apply to normal triangles.(more about triangle types) therefore, when you are trying to prove that two triangles are congruent, and one or both triangles, are isosceles you have a few theorems that you can use to make your life easier.

step-by-step explanation:

an isosceles triangle has two congruent sides and two congruent angles. the congruent angles are called the base angles and the other angle is known as the vertex angle. ∠bac and ∠bca are the base angles of the triangle picture on the left. the vertex angle is ∠abc

6 cm

step-by-step explanation: