Need !
john the trainer has two solo workout plans that he offers his clients: plan a and plan b. each client does either one or the other (not both). on friday there were 3 clients who did plan a and 5 who did plan b. on saturday there were 9 clients who did plan a and 7 who did plan b. john trained his friday clients for a total of 6 hours and his saturday clients for a total of 12hours. how long does each of the workout plans last?

45 minutes each

Step-by-step explanation:

Set Plan A clients as x and Plan B clients as y to make a system of equations, the constant is the number of hours worked.

3x+5y=6

9x+7y=12

Now solve using substitution or elimination.  I will use elimination.

-9x-15y=-18 I multiplied the whole first equation by -3 to eliminate x.

9x+7y=12, add the equations

-8y=-6 solve for y

y= 3/4 of an hour or 45 minutes

Next plug y into either equation

3x+5(3/4)=6 Solve for x.

3x+15/4=6

3x=2.25

x=0.75, also 45 minutes

To check plug in each variable value to each equation to see if they work if you need to.

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}