Consider the table of values for function f.
x: -1, 0, 1, 2, 3, 4, 5
f(x): 3.5, 4, 5, 7, 11, 19, 35
the function g is shown below:
g(x)=4x+5
in which of the following intervals is the average rate of change greater for f than for g?
a. [1,3]
b. [3,5]
c. [0,2]
d. [-1,0]

B. [3,5]

Step-by-step explanation:

The rate of change of a function is the same as the slope between two given points from that same function,

Hence,

all we need to do is use the slope's equation, that is

And eval it in every couple of ordered pairs given from the table we obtain the following>

x2y2x1y1  m

04-13,5  0,5

1504  1

2715  2

31127  4

419311  8

535419  16

The rate of change from g(x) is 4 (its slope)

Hence, the interval when the rate of change of f(x) is greater than g(x) is from x=3 to x=5

the answer is d. (1.2, -4.7) on edgn

hope this !