Can anyone me with this pre calc question?

y=4x-4

Step-by-step explanation:

The equation of a line is slope-intercept form is: y=mx+b where m is the slope and b is the y-intercept. This is the required form I think. Your document says write in slope... can't read the rest because it is cut off.

I'm actually going to use point-slope form which is: y-y1=m(x-x1) where m is the slope and (x1,y1) is a point we know that is on the line.

We have m=4.

We can actually find a point on the line. Both the line and the curve y=x^2 cross at x=2.

So we find the corresponding y-coordinate on our line to x=2 by plugging into x^2.

x^2 evaluated at x=2 gives us 2^2=4.

So we have the slope m=4 and a point (x1,y1)=(2,4) on the line.

Let's plug it into the point-slope form:

y-4=4(x-2)

Now the goal was y=mx+b form so let's solve our for y.

y-4=4(x-2)

Distribute 4 to terms in ( ):

y-4=4x-8

Add 4 on both sidea:

y=4x-4

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

he has now walked a total of what?

if i know what this is maybe i can

step-by-step explanation: