As part of a new advertising campaign, a beverage company wants to increase the dimensions of their cans by 1.11. if the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm2, how much more will the new cans hold? use 3.14 for π and round your answer to the nearest hundredth.
802.91 cm^3
376.42 cm^3
463.79 cm^3
124.67 cm^3

The amount the new can will hold more than the previous can is:

                            124.67 cm³

If the cans are currently 12 cm tall, 6 cm in diameter, and have a volume of 339.12 cm³.

Now, if the dimension of the can is increased by 1.11

Then the height of the new can will be: 12×1.11

Height of new can= 13.32 cm

and the diameter of new can will be= 6×1.11

                                                            = 6.66 cm

Hence, radius of can=6.66/2=3.33 cm

Hence, the  volume of the new can will be= πr²h

where r is the radius of the can and h is the height of the can.

Hence, the Volume of the new can will be:

Volume=3.14×(3.33)²×13.32

i.e.

Volume of new can = 463.79 cm³.

Hence, the difference in the volume is:

Volume of new can-Volume of previous can

=   463.79-339.12

= 124.67 cm³

439400

step-by-step explanation:

130^2 = 16900

16900*26 = 439400

more detail

step-by-step explanation: