Arectangle has a length 10 m less than twice its width. when 2 m are added to the width, the resulting figure is a square with an area of 196 m squared. find the dimensions of the original rectangle.

The length of the original rectangle is 14 meters and the width of the original rectangle is 12 meters

Step-by-step explanation:

Let

l ----> the length of the original rectangle

w ----> the width of the original rectangle

we know that

----> equation A

----> area of a square

Solve for w

square root both sides

-----> this solution not make sense

so

Find the value of L

therefore

The length of the original rectangle is 14 meters and the width is 12 meters

answer: 457.14

step-by-step explanation:

205 - 45 = 160

160 / .35 = 457.142857

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1