Compare the functions shown below:
g(x)
f(x) = −6x − 3 cosine function with y intercept at 0, negative 3
h(x) = 2 cos(x + π) − 1
using complete sentences, explain which function has the greatest y-intercept.

All the graphs have the same value for the y-intercept which is -3.

Step-by-step explanation:

My assumption is this:

g(x) is the graph given,

f(x)=-6x-3, and

h(x)=2cos(x+π)-1

are the given functions.

You will have to correct this assumption if this is not right.

You are asked to find the y-intercept of each graph and then say which of the functions has the greatest y-intercept.

The y-intercept is at x=0; the order pair (0,something).  0 means we go left and right none from the origin which will keep us on the y-axis because the something number I have as the y-coordinate of this point will either tell us to go up or down or stay there at origin.

So the y-intercept of f(x)=-6x-3 is when x=0.

f(0)=-6(0)-3

f(0)=  0   -3

f(0)=      -3

The y-intercept of f is -3.

Now g is the graph.  The y-intercept is where it crosses the y-axis.  It is again when you have x=0.  That happens at y=-3.

The y-intercept of g is -3.

So the y-intercepts of f and g are the same.

Finally let's look at h:

h(x)=2cos(x+π)-1 has y-intercept at x=0.

h(0)=2cos(0+π)-1

h(0)=2cos(π)    -1

h(0)=2(-1)          -1

h(0)=-2             -1

h(0)=-3

The y-intercept of h is -3.

All the graphs have the same value for the y-intercept which is -3.

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

2 apples

step-by-step explanation:

taking away equals subtraction. 6-4=2