You play a game where you are given 2 dollars. then you flip a coin. if it’s heads, you double your money. if it’s tails, the game ends and you walk away with your money. how much are you willing to pay to play?

Answer with explanation:

→Probability of getting head when you toss a coin once

                =50%

Probability of getting tail when you toss a coin once

                =50%

So, probability of winning as well as loosing is 50%.

→Money provided for playing the game =$ 2

→As it is given that, when a coin is flipped once , if head appears you double your money and if it is tail you walk away with your money.

→As losing cost me nothing ,that is still i am gettng $ 2, so i will go with the toss .

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.