Aline passes through (9,-9) and (10,-5).
a. write an equation for the line in point-slope form.
b. rewrite the equation in standard form using integers.
y-9 = 46% + 9); -4x + y = 45
y + 9 = 4(x + 9); -4% + y = -45
y + 9 = 4(-9); -4x + y = -45
y - 9 = 40%-9); -4% + y = 45

just a quick note

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

now, however the inappropriate choices here, do have it with a negative "x".

y + 9 = 4(x - 9); -4x + y = -45

Step-by-step explanation:

According to the Point-Slope Formula [y - y₁ = m(x - x₁)], all the negative symbols give the OPPOSITE terms of what they really are, so put the coordinates into their correct positions, depending on the signs. In the equation, there is a 9 in it [-(-9) = 9], according to the formula. By the way, this is its y-coordinate. The x-coordinate is 9, which is normal, according to the formula (see part of above answer in parentheses). So now, this is how your work will look:

y + 9 = 4x - 36 [Point-Slope Form]↷

- 9- 9

y = 4x - 45 [Slope-Intercept Form]↷

-4x -4x

-4x + y = -45 [Standard Form]

Here we are at this second equation.

I am joyous to assist you anytime.

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