the standard form of the equation of a parabola is y= x2 - 8x + 29.
what is the vertex form of the equation?
o a. y=(x-4)2 + 13
o b. y=(x-4)2 + 18
o c. y = (x+4)(x-4) + 13
o d. y= (x-4)2 + 28

A

Step-by-step explanation:

Put brackets around the first two tems.

y = (x^2 - 8x) + 29

Take 1/2 coefficient of the linear term -8. Square that result. Add it inside the brackets.

1/2 (- 8) = - 4

(- 4)^2 = 16

y = (x^2 - 8x + 16) + 29

Subtract 16 outside the brackets.

y = (x^2 - 8x + 16) + 29 - 16  

Do the subtraction

y = (x^2 - 8x + 16) + 13

Represent what is inside the brackets as a square.

y = ( x - 4)^2 + 13

The answer is A

you answer is a

step-by-step explanation: