How can x^2+3x+1=2x^2+2x+3 be set up as a system of equations?

System of equations of x^2+3x+1=2x^2+2x+3 is x^2-x+2=0.

Step-by-step explanation:

We need to make system of equations of:

x^2+3x+1=2x^2+2x+3

Solving,

Adding -2x^2 on both sides

x^2+3x+1-2x^2=2x^2+2x+3-2x^2

-x^2+3x+1=2x+3

Adding -2x on both sides

-x^2+3x+1-2x=2x+3-2x

-x^2+x+1=3

Adding -3 on both sides

-x^2+x+1-3=3-3

-x^2+x-2=0

Multiplying with -1

x^2-x+2=0

System of equations of x^2+3x+1=2x^2+2x+3 is x^2-x+2=0.

the answer is c.

step-by-step explanation:

one set of data has more variation than the other. hope this !