If \cot \theta =\sqrt{3}cotθ= 3 and the reference angle of \thetaθ is 30^\circ30 ∘ , find both angles in degrees from 0^\circ\le \theta < 360^{\circ}0 ∘ ≤θ< 360 ∘ and both angles in radians from 0 \le \theta < 2\pi.0≤θ< 2π.

if this is really you s much. i only have 3 points left and i have 2 questions to ask

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

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step-by-step explanation: