Aball is launched into the air from below a cliff, such that after t seconds its height above the cliff top is hmetres, and is given by the equation
h =  − 4.9t^2 + 19.6t − 12.6.
calculate, to the nearest metre, the maximum height the ball achieves above the cliff top.

7 meters

Step-by-step explanation:

In order to find the answer we need to calculate the first derivative of the function as follows:

Now, for obtaining the time 't' when the ball reaches the maximum height:

Finally, we use the original equation for determining the height after 2 seconds:

In conclusion, the maximum height above the cliff top is 7 meters.

unless if u could do my questions, if not i wouldn't want to

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.