solve the following initial value problem (ode):
a) y" + 4y = -2 , y(pi/8) = 1/2 , y'(pi/8) = 2
b)5y" + y' = -6x , y(0) = 0 , y'(0) = -10
c) 2y" + 3y' - 2y = 14x^2 - 4x - 11 , y(0) =0 , y'(0) = 0
show all steps.

11 feet 6 inches and 8 feet 6 inches

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

the aswere is the one with all 8's and the second one is with the 10,8 and 6

step-by-step explanation:

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.