During a research experiment, it was found that the number of bacteria in a culture grew at a rate proportional to its size. at 1010: 00 am there were 4 comma 0004,000 bacteria present in the culture. at noon, the number of bacteria grew to 4 comma 6004,600. how many bacteria will there be at midnight?

68600 will there be at midnight ( approx )

Step-by-step explanation:

Let P shows the population of the bacteria,

Since, the number of bacteria in a culture grew at a rate proportional to its size,

Where, k is the constant of proportionality,

Now, let the population of bacteria is estimated from 10:00 AM,

So, at t = 0, P = 4,000 ( given )

Now, at noon there are 4,600 bacterias,

That is, at t = 2, P = 4600

Hence, the equation that represents the population of bacteria after t hours,

Therefore, the population of the bacteria at midnight ( after 14 hours ),

i think that you should ask google for the answer to that problem because if we don't know it google does

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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