Solve the ivp dy/dt = 2t/(y + t^2 y), y(0) = -2.

Step-by-step explanation:

Given that

This is a differential equation.

Now by separating variables

Now by integrating both side

Now by soling above integration

We know that  integration of dx/x is lnx.

Where C is the constant.

Given that when t=0 then y= -2

So by putting the above values of t and y we will find C

4=2 ln(1)+C     (we know that ln(1)=0)

So C=4

⇒

So solution of above equation is  

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

do your own work and don"t cheat.

step-by-step explanation: