Write the standard form of the line that has a slope of -3/4 and y -intercept of -2. include your work in your final answer.

3x + 4y = - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - and c = - 2, hence

y = - x - 2 ← equation in slope- intercept form

The equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

Multiply the terms in the slope- intercept form equation by 4

4y = - 3x - 8 ( add 3x to both sides )

3x + 4y = - 8 ← in standard form

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50