Aregular hexagon has a radius of 20in. what is the approximate area of the hexagon

A= 1038 in²

Step-by-step explanation:

There are several ways to find the area of a regular hexagon

In a regular hexagon, split the figure into triangles.

Find the area of one triangle.

Multiply this value by six.

We will apply the formula of area of regular polygon:

A= 1/2r²nsin(360/n)

r = radius

n = number of sides of the regular polygon

We know that,

r= 20 in

n= 6

Now substitute the values in the formula:

A= 1/2(20)²(6)sin(360/6)

A= (20)²(3)sin(360/6)

A= (20)²(3)sin(60)

A=3*(20)² *√3/2

A= 1200 * √3/2

A= 600*√3

A= 1038 in²

Therefore the approximate area of hexagon is 1038 in²

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)