Arnold invested $64,000, some at 5.5% interest and the rest at 9%. how much did he invest at each rate if he received $4,500 in interest in one year?

The amount invested at 5.5% was $36,000 and the amount invested at 9% was $28,000

Step-by-step explanation:

we know that

The simple interest formula is equal to

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

Let

x -----> the amount invested at 5.5%

(64,000-x) -----> the amount invested at 9%

in this problem we have

so

substitute the given values

therefore

The amount invested at 5.5% was $36,000 and the amount invested at 9% was $28,000

repeat the question

step-by-step explanation:

0.6

39mph

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