If the graph of the function f defined by
f(x)=3x^2-5
is translated vertically upward by 8 units, it becomes the graph of a function g.
find the expression for g(x)

g(x) = 3x^2 + 3.

Step-by-step explanation:

f(x) = 3x^2 - 5.

First, the x-intercepts have to be calculated to determine the line of symmetry of f(x). For that, set f(x) = 0. Therefore:

3x^2 - 5 = 0.

x^2 = 5/3

x = 1.29 and x = -1.29. The midpoint of these two x-coordinates will be the line of symmetry, which is x = 0.

Therefore, if the graph is translated vertically upwards, it will move up the y-axis by the given amount. In this question, the amount is 8. Simply add 8 in f(x) to obtain g(x). Therefore:

g(x) = f(x) + 8.

g(x) = 3x^2 - 5 + 8.

g(x) = 3x^2 + 3.

Therefore, g(x) = 3x^2 + 3!!!

d

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.