If a and b are both positive, two-digit integers, is a + b a multiple of 11? the tens digit of a is equal to the units digit of b, and the tens digit of b is equal to the units digit of a both a and b are odd.

Yes!

Step-by-step explanation:

Let x be the tens place and y be the units place. x and y need to be odd because in other case a or b will not be odd. For example, if x=1 and y=2 a will be 21 but b will be 12 that is not odd.

Now, a+b = xy+yx. Note that xy is not x*y, is just the digits concatenated.Then, there are two cases:

If x+y<10 then xy+yx = (x+y)(x+y) (again, that is not a multiplication is x+y concatenated with x+y) and that is 11*(x+y) a multiple of 11.

If x+y≥10 then xy+yx = (x+y+1)(x+y-10) because x+y<20.

Now we are going to see that last result without the concatenation, as a sum, that is

(x+y+1)*10 + x+y-10 = 10x+10y+10+x+y-10 = 11x+11y = 11(x+y). This result is clearly a multiple of 11.

In conclusion, in all cases the result of a+b is a multiple of 11.

687.09 dollars       happy now

step-by-step explanation: 6870

1857 times .63 equals 1169.91 subtract that from 1857 you get 687.09