Factor the sum or and then chose the correct answer from the options below.

Factor the sum of 27u^3+64 is (3u+4)(9u^2-12u+16)

Option B is correct.

Step-by-step explanation:

We are given:

27u^3+64

It can be written as:

(3u)^3+(4)^3

The formula used for a^3+b^3 is

a^3 + b^3 = (a+b)(a^2-ab+b^2)

here a = 3u and b = 4

Putting values and finding

(3u)^3+(4)^3 =(3u+4)((3u)^2-(3u)(4)+(4)^2)

(3u)^3+(4)^3 =(3u+4)(9u^2-12u+16)

So, Factor the sum of 27u^3+64 is (3u+4)(9u^2-12u+16)

Option B is correct.

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

-8

step-by-step explanation: