Amajor cell phone service provider has determined that the number of minutes per month that its customers use their phone is normally distributed with mean equal to 445.5 minutes and standard deviation equal to 22.75 minutes. the company is thinking of charging a lower rate for customers who use the phone the most. if it wishes to give the rate reduction to no more than 9 percent of its customers, what should the cut-off be?

we can say that the cut-off= 476.125 minutes

Step-by-step explanation:

mean = 445.5 minutes

standard deviation = 22.75 minutes

rate reduction not more than = 9%

The z score corresponding to (100-9)%= 0.91 is 1.35

by standard normal Table

we use

on calculating we get

x= 476.2125 minutes

Therefore, we can say that the cut-off= 476.125 minutes

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: