If (x − 6) is a factor of the polynomial function f(x) = 5x2 − 28x − 12, which of the following is another factor?
(5x − 2)
(5x + 2)
(2x − 5)
(2x + 5)

(5x + 2)

Step-by-step explanation:

The product of (ax + b) and (cx + d) is:

(ax + b) (cx + d) = ac x² + (ad + bc) x + bd

The leading coefficient is the product of the coefficients of each factor.

The constant is the product of the constants of each factor.

So if (x − 6) is a factor of 5x² − 28x − 12, the other factor must have a coefficient of 5 and a constant of 2.

(5x + 2)

a² + b²= c²

24² + 7² = c²

c= 25

why can't you?

step-by-step explanation: