Mathematics, 05.08.2019 22:20 1162

Consider the following.3x + 3y = 8(a) find y' by implicit differentiation.(b) solve the equation explicitly for y and differentiate to get y' in terms of x.(c) check that your solutions to part (a) and (b) are consistent by substituting the expression for y into your solution for part (a).y' =

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Answer from: LikeIke2859

a.y'=-1

b.y'=-1

c.Yes

Step-by-step explanation:

We are given that consider a function

3x+3y=8

Implicit function: That function is a relation in which dependent variable can not be expressed in terms of independent variable

Explicit function: It is that function in which dependent variable can be expressed in terms of independent variable.

a. 3x+3y=8

Differentiate w.r.t x then we get

$3+3\frac{dy}{dx}=0$

$3\frac{dy}{dx}=-3$

$\frac{dy}[dx}=\frac{-3}{3}=-1$

$\frac{dy}{dx}=y'=-1$

b. 3x+3y=8

3y=8-3x

$y=\frac{8-3x}{3}$

Differentiate w.r.t x then we get

$\frac{dy}{dx}=\frac{-3}{3}=-1$

$\frac{dy}{dx}=y'=-1$

When we substituting the value of y obtained from part b into a solution of part a then we get

y'=-1

Hence, solutions are consistent.

Answer from: Quest

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200. after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes 1800 - 6400 which gets you 11,600.

Answer from: Quest

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

$x^2-2x+y^2-6y=26$

we now create space between the x and y terms with parenthesis.

$(x^2-2x)+(y^2-6y)=26$

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

$\frac{-2}{2} =(-1)^{2} =1$

$\frac{-6}{2} =(-3)^{2} =9$

we add the squares to both sides.

$(x^2-2x+1)+(y^2-6y+9)=26+1+9$

simplify.

$(x^2-2x+1)+(y^2-6y+9)=36$

and write the quadratics in factored form.

$(x-1)^{2} +(y-3)^{2} =36$

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

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Consider the following.3x + 3y = 8(a) find y' by implicit differentiation.(b) solve the equation exp...

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