Adog chasing a rabbit, rabbit runs 60 leaps before the dog. when the dog jumps 2 leaps rabbit can jumps 3 leaps. but rabbit have to jump 7 leaps to cover the distance that dog cover by 3 leaps. how many leaps that the dog jumps when rabbit and dog meet?

72 leaps

Step-by-step explanation:

Given: A dog chasing a rabbit, rabbit runs 60 leaps before the dog. When the dog jumps 2 leaps rabbit can jumps 3 leaps. But rabbit have to jump 7 leaps to cover the distance that dog cover by 3 leaps.

To Find: number of leaps that the dog jumps when rabbit and dog meet.

Solution:

Let the units of leaps jumped by rabbit be r

Let the units of leaps jumped by  dog  be d

7 leaps of rabbit =3 leaps of dog

rabbit runs 60 leaps before the dog,

therefore

distance between dog and rabbit=60r=

When the dog jumps 2 leaps rabbit can jump 3 leaps

speed of rabbit()==

speed of dog() =

As dog and rabbit are running is same direction,

relative speed of dog and rabbit ()=speed of dog-speed of rabbit

                                             ()-()

the distance to be covered by dog before catching rabbit

Now,

leaps jumped by dog in of time

Hence the leaps jumped by dog when dog and rabbit meet are 72

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

the answer is d. (1.2, -4.7) on edgn

hope this !