10) one-fifth the sum of 2 consecutive integers is 29 less than the larger of the 2 consecutive integers. find the
smaller of the 2 consecutive integers.
hi, im studying for a test and needed with this question, to anyone who does.

47

Step-by-step explanation:

Let the smaller integer be n and the consecutive integer be n+1.

According to the question,

(n+n+1)/5 + 29=n+1

or,(2n+1)/5 + 29=n+1

or,2n+1+145=5n+5

or,3n=141

or,n=47

and n+1=48

So, the smaller of the two integer is 47

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.