Mathematics, 06.08.2019 01:20 MrSavannahCat
In rectangle $abcd$, $p$ is a point on $bc$ so that $\angle apd=90^{\circ}$. $ts$ is perpendicular to $bc$ with $bp=pt$, as shown. $pd$ intersects $ts$ at $q$. point $r$ is on $cd$ such that $ra$ passes through $q$. in $\triangle pqa$, $pa=20$, $aq=25$ and $qp=15$. find $sd$. (express your answer as a common fraction.)
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In rectangle $abcd$, $p$ is a point on $bc$ so that $\angle apd=90^{\circ}$. $ts$ is perpendicular t...
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