In δbca, cb = 11 cm, cg = 6 cm, ah = 9 cm. find the perimeter of δbca. triangle bca with inscribed circle d. segments bf and bh, cf and cg, and ag and gh are tangent to circle d. 32 cm 40 cm 35 cm 42 cm

The perimeter of Δ ABC is 40 cm ⇒ 2nd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- Circle D is inscribed in triangle ABC

- The circle touches the side AB at H , side BC at F , side CA at G

- BF and BH are tangents to circle D from point B

∴ BF = BH ⇒ tangents drawn from a point outside the circle

- CF and CG are tangents to circle D from point C

∴ CF = CG ⇒ tangents drawn from a point outside the circle

- AG and AH are tangents to circle D from point A

∴ AG = AH ⇒ tangents drawn from a point outside the circle

∵ CG = 6 cm ⇒ given

∴ CF = 6 cm

∵ CB = 11 cm ⇒ given

∵ CB = CF + FB

∴ 11 = 6 + FB ⇒ subtract 6 from both sides

∴ FB = 5 cm

∵ FB = BH

∴ BH = 5 cm

∵ AH = 9 cm ⇒ given

∵ AH = AG

∴ AG = 9 cm

∵ AB = AH + HB

∴ AB = 9 + 5 = 14 cm

∵ AC = AG + GC

∴ AC = 9 + 6 = 15 cm

∵ BC = 11 cm ⇒ given

∵ The perimeter of Δ ABC = AB + BC + CA

∴ The perimeter of Δ ABC = 14 + 11 + 15 = 40 cm

* The perimeter of Δ ABC is 40 cm

3,750 deer

step-by-step explanation:

1,500 is 15 times larger than 100

lets make 250 15 times larger.

3750 deer

how do heroes resolve conflicts in beowulf?

question 15 options:

they sue each other in court

they get a mediator

the seek counseling

they get even or take revenge

step-by-step explanation: