What is the perimeter and area of a rectangle with a length of 14 cm and a width that is 5 more than twice the length?

Area: 462cm

Step-by-step explanation:

"More than twice the length" The length is 14. Twice the length would mean 14×2 which equals 28.

Adding 5 to 28 would make 33.

Then multiply the way you normally would when calculating area: l×h

33cm×14cm=462cm

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a