The times for the mile run of a large group of male college students are approximately normal with mean 7.09 minutes and standard deviation 0.77 minutes. use the 68-95-99.7 rule to answer the following questions. (start by making a sketch of the density curve you can use to mark areas on.) (a) what range of times covers the middle 68% of this distribution? (b) what percent of these men run a mile in more than 9.4 minutes? (a) from 6.32 minutes to 7.86 minutes (b) 13 %

answer: you need the equation in the question so i can answer it

step-by-step explanation:

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)

explanation:

step-by-step explanation: