Can anyone pl me with this question of linear equation in two varaiable its very plz solve it for

That's not a linear system, but you have an awesome school system for giving you this problem.

Multiply by 6xy to clear the fractions.

That's a second degree equation, also known as a conic.  That one happens to be a hyperbola.  

Let's clear the fractions from the second equation, multiplying out common denominator xy:

We are being asked to find the meet of two hyperbolas, so we expect two answers, a quadratic equation.

Substituting,

We have to rule out x=0 because it's in the denominator.

(44/19, 33/20)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.