Acommittee of 15 people is holding elections today. the positions on the ballot are: chairman, vice? chairman, parliamentarian, recording secretary, and treasurer. if each position is to be held by one person and no person can hold more than one position, in how many ways can those positions be filled?

There are 360,360 ways that those positions can be filled.

Step-by-step explanation:

Since we have given that

Number of position = 5

As follows :

Chairman, Vice chairman, parliamentarian, recording secretary, and treasurer.

Number of people is holding elections today = 15

Number of positions that can be filled is given by

Hence, there are 360,360 ways that those positions can be filled.

yes   because as the functions are graphed they eventually will intersect unless otherwise

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt