Consider a complete (thus the hamiltonian cycle exists) weighted graph g, in which the weights are the euclidean distance between nodes. show that the shortest hamiltonian cycle cannot intersect itself.

i want to die

what the hell man, i just want the points lol

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17

if you're trying to figure out how much each ounce cost it would be 0.20

cents each ounce

for this case we have that by definition, the surface area of a cylinder is given by:

where:

r: it is the radius of the cylinder

h: it is the height of the cylinder

we can also rewrite it as:

where:

la: it's the lateral area

ba: area of the base

option a