You select a family with three children. it m represents a male child, and f represents a female child, the set of equally likely outcomes for the children's genders is (mmm, mimf mfm, mff, fmm, fmf, ffm, fff ) find the probability of selecting a family with fewer than 5 male children p(fewer than 5 male children) type an integer or a simplified fraction.)

Answer with explanation:

→If a Family has five children, then Total likely outcome can be represented as:

Five Male =1

Five Female =1

4 Male +1 Female =4

4 Female +1 Male =4

3 Male +2 Female =10

3 Female +2 Male =10

Total Possible Outcome

 =1+1+4+4+10+10

or

   =2×2×2×2×2

     =32

,i.e either a children can be a male or female.

→If all the five childrens are male , then in the family number of children fewer than 5 male children =32-1=31

→Probability of an Event

→→Probability of selecting a family with fewer than 5 male children

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this

360/29

step-by-step explanation: