The angle of depression from the top of a lighthouse to the base of a boat out at sea is 10°. if the lighthouse is at the
edge of land and is 82 meters tall, approximately how far out at sea is the boat?
15 m
176 m
465 m
711 m

Option C (465 meters).

Step-by-step explanation:

This question can be solved using one of the three trigonometric ratios. The height of the lighthouse mentioned is 82 meters and the angle of depression is 10°. It can be seen that the required distance is given by x meters. This forms a right angled triangle, as it can be seen in the diagram. The perpendicular is given by 82 meters, the base is unknown, and the angle of 10° is given, as shown in the attached diagram. Therefore, the formula to be used is:

tan θ = Perpendicular/Base.

Plugging in the values give:

tan 10 = 82/x.

x = 82/tan 10.

x = 465.045109209  meters .

Therefore, the boat is 465 meters (to the nearest meters) far out in the sea. Therefore, the answer is Option C!!!

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

it would rotate about 180 degrees.