(draw a diagram modeling the scenario and solve. round all decimals to the nearest tenth. ) a 15-foot ladder is leaning against a tree. if the ladder reaches 10 feet high on the tree, how far is the base of the
ladder from the tree?

11.18 feet

Step-by-step explanation:

This is a pythagorean theorem problem.  You should draw a ladder as a diagonal line with the top resting on a vertical line (the wall) an the bottom on a horizontal line (the ground.  Then the ground and the wall should connect to make a right tiangle.  

The ladder is the c in a^2+b^2=c^2, and the wall and ground can be either.  I am going to call the wall b which will make the ground a.  So now we have

a^2 + b^2 = c^2

a^2 + 10^2 = 15^2

a^2 + 100 = 225

a^2 = 125

a = 11.18

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.