The solution of the equations x + 2y = 1.5 and 2x + y = 1.5 is
(a) x = 1 and y = 1
(b) x = 1.5 and y = 1.5
(c) x = 0.5 and y = 0.5
(d) none of these

C

Step-by-step explanation:

Given the 2 equations

x + 2y = 1.5 → (1)

2x + y = 1.5 → (2)

Rearrange (1) expressing x in terms of y by subtracting 2y from both sides

x = 1.5 - 2y → (3)

Substitute x = 1.5 - 2y in (2)

2(1.5 - 2y) + y = 1.5 ← distribute left side

3 - 4y + y = 1.5

3 - 3y = 1.5 ( subtract 3 from both sides )

- 3y = - 1.5 ( divide both sides by - 3 )

y = 0.5

Substitute y = 0.5 into (3) for corresponding value of x

x = 1.5 - (2 × 0.5) = 1.5 - 1 = 0.5

Solution is x = 0.5 and y = 0.5 → C

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

he kicked it up? is this the answer ?

step-by-step explanation: