What is the growth factor of each geometric sequence?
a.
1,1,1,1,1
b.
256, 128, 64
c.
18, 54, 162
d.
0.8, 0.08, 0.008
e.
0.008, 0.08, 0.8

For each sequence, the growth factors are:

To find the growth factor of each sequence, we divide each term by it's previous term.

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Question a:

The growth factor of the sequence is 1.

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Question b:

The growth factor of the sequence is 0.5.

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Question c:

The growth factor of the sequence is 3.

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Question d:

The growth factor of the sequence is 0.1.

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Question e:

The growth factor of the sequence is 10.

A similar question is found at link

Step-by-step explanation:

1,1,1,1,1                          *1    Multiply by 1

.

256, 128, 64            * 1/2    divide into 2

18, 54, 162               *3    Multiply by 3

0.8, 0.08, 0.008     * 1/10      Divide into 10

e.

0.008, 0.08, 0.8      *10    Multiply by 10

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

what is the answer?