Find the center and radius of the circle with the equation (x-4)²+(y+6)²=16

Center:  

Radius:

Step-by-step explanation:

It is necessary to remember that the Equation of the circle in Center-radius form, is:

Where the center of the circle is at the point (h, k) and the radius is "r".

Then, given the following equation of the circle:

We can notice that it is written in Center-radius form. Then we can identify that:

Therefore the center is:

And the radius is:

Center = ( 4, -6) ; radius = 4.

Step-by-step explanation:

Given : (x-4)²+(y+6)²=16.

To find :  Find the center and radius of the circle with the equation.

Solution : We have given (x-4)²+(y+6)²=16.

We can write is as (x-4)²+(y+6)²= 4².

Standard form of circle : (x – h)² + (y – k)² = r².

Where (h ,k) is center

r =  radius .

On comparing (x-4)²+(y+6)²=16 with (x – h)² + (y – k)² = r².

(h,k) = ( 4 , -6)

r = 4.

Therefore, Center = ( 4, -6) ; radius = 4.

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation: