Jamal throws a golf ball straight up from a height of 5 feet and at a speed of 75 feet per second. the height of the ball in feet is given by the polynomial
−16t^2 + 75t + 5, where t is the time in seconds. how high is the ball after 4 seconds?

49 ft.

Step-by-step explanation:

-16[4]² + 75[4] + 5

-16[16] + 300 + 5

-256 + 300 + 5 = 49

I am joyous to assist you anytime.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐