Aprojectile if fired from ground level with an initial velocity of 35 m/s at an angle of 35° with the horizontal. how long will it take for the projectile to reach the ground?

  about 4.097 seconds

Step-by-step explanation:

The vertical velocity is ...

  (35 m/s)sin(35°) ≈ 20.075 m/s

When the projectile reaches the level from which it was launched (ground level), its final velocity will be the opposite of its initial velocity. Thus, the change in velocity is ...

  -20.075 -(20.075) = -40.150 . . . . m/s

The acceleration is provided by gravity, which is -9.8 m/s², so the time required is ...

  t = Δv/a = (-40.150 m/s)/(9.8 m/s²) ≈ 4.097 s

ian gonna lie that is way to much