You measure the weight of 49 backpacks, and find they have a mean weight of 67 ounces. assume the population standard deviation is 8.8 ounces? . based on this, what is the maximal margin of error associated with a 94% confidence interval for the true population mean backpack weight.

2.36

Step-by-step explanation:

The formula to find the margin of error is given by :-

Given : Significance level :

Critical value :   [Using standard normal distribution table]

Sample size : n=49

Standard deviation : 8.8 ounces

Then , the margin of error will be :-

Hence, the margin of error associated with a 94% confidence interval for the true population mean backpack weight = 2.36

4

step-by-step explanation:

im pretty sure it's 4 beacsue 8/2 equals 4

t

step-by-step explanation:

ever thing time 1 is a multiply by 1 it get