Two circles that have two common external tangents but no common internal tangents

$4

step-by-step explanation:

$30×5=$150

$150 minus $130=$20

$20÷5=$4.

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answer: c

substitute in the values.

for a:

f(0) = 0 + 9

f(0) = 9

a is a solution.

for b:

f(7) = 14 + 9

f(7) = 23

b is a solution.

for c:

f (3) = 6 + 9

f(3) = 15

c is not a solution. it's supposed to be 14.

for d:

f(2) = 4 + 9

f(2)= 13

d is a solution.

i believe b is the answer