Cloud seeding simpson, alsen, and eden (technometrics 1975) report the results of trials in which clouds were seeded and the amount of rainfall recorded. the authors report on 26 seeded and 26 unseeded clouds in order of the amount of rainfall, largest amount first. here are two possible tests to study the question of whether cloud seeding works. paired t-test of m(1 - 2) mean of paired differences = -277.39615 t-statistic = -3.641 with 25 df p = 0.0012 2-sample t-test of m1 - m2 difference between means = -277.4 t-statistic = -1.998 with 33 df p = 0.0538 a) which of these tests is appropriate for these data? explain. b) using the test you selected, state your conclusion.

step-by-step explanation:

just plug in each number for x and see which ones work and don't

312312

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.