Abasketball coach will select the members of a five-player team from among 9 players, including john and peter. if the five players are chosen at random, what is the probability that the coach chooses a team that includes both john and peter?

Step-by-step explanation:

Given that a basketball coach will select the members of a five-player team from among 9 players, including John and Peter.

Out of nine players five are chosen at random.

The team consists of John and Peter.

Hence we can sort 9 players as I group, John and Peter and II group 7 players.

Now the selection is 2 from I group and remaining 3 from II group.

Hence no of ways of selecting a team that includes both John and Peter==35

Total no of ways = =126

= =

h/o/e/s mad

step-by-step explanation:

si si si

the answer should be:

a. 3, 4, and 6

b. 18, 24, and 36

c. 4.8, 6.4, and 9.6

hope i

-lavira : )